php - Preg_match_all grab value from string -

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example:

$word = "your ip address=10.0.0.1</br>my ip address=127.0.0.1</br>";

how can taking ip address string using preg_match_all?

a pragmatic attempt in case match between = , </br>:

preg_match_all('~=(.*?)</br>~', $string, $matches); var_dump($matches);

note ? marks ungreedy match. if omit following match:

10.0.0.1</br>my ip address=127.0.0.1

of course need preg_match_all() every match (ip) not first.


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