How to alphabetically sort 2D array based on an element, without using the built-in sort function? (python) -

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i've been stuck on while, 1 please me?

suppose have array:

[[231,cow,234334,2231319,323242],[3,alien,2,2312,3212],[9,box,234,2319,3242]]

can me create sort function sorts array alphabetically based on 2nd element of each individual array in larger array, looks like:

[[3,alien,2,2312,3212],[9,box,234,2319,3242],[231,cow,234334,2231319,323242]]

here simple bubble sort 1 of easiest sorts understand (since looks homework.) key, think, instructor trying think 2d aspect, here means need @ second element of second column in compare. have modified compare this. tested , need put quotes around elements strings.

   def bubblesort( ):      in range( len( ) ):        k in range( len( ) - 1, i, -1 ):          if ( a[k][1] < a[k - 1][1] ):            swap( a, k, k - 1 )     def swap( a, x, y ):      tmp = a[x]      a[x] = a[y]      a[y] = tmp     a=[[231,'cow',234334,2231319,323242],[3,'alien',2,2312,3212],[9,'box',234,2319,3242]]    print    bubblesort(a)    print

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