PHP's hash() in Java -

i trying java generate same hash string php's hash algorithm does.

i have come close enough:

hash('sha512', 'password'); 

outputs:

b109f3bbbc244eb82441917ed06d618b9008dd09b3befd1b5e07394c706a8bb980b1d7785e5976ec049b46df5f1326af5a2ea6d103fd07c95385ffab0cacbc86 

java code:

public static void main(string[] args) {     hash("password"); }  private static string hash(string salted) {     byte[] digest;     try {         messagedigest mda = messagedigest.getinstance("sha-512");         digest = mda.digest(salted.getbytes("utf-8"));     } catch (exception e) {         digest = new byte[]{};     }      string str = "";     (byte adigest : digest) {         str += string.format("%02x", 0xff & adigest);     }      return str; } 

this outputs same.

my problem when use third argument within php's hash function. on php's site it's described following:

raw_output     when set true, outputs raw binary data. false outputs lowercase hexits. 

i not quite sure how implement parameter. think question be, how convert string object binary string object? currently, running php generates following: http://sandbox.onlinephpfunctions.com/code/a1bd9b399b3ac0c4db611fe748998f18738d19e3

this should reproduce outcome link:

string strbinary = null; try {     strbinary = new string(digest, "utf-8"); } catch (unsupportedencodingexception e) { } 

and you'll need these imports @ top of file:

import java.nio.charset.charset; import java.io.unsupportedencodingexception; 

i hope understood issue correctly.