shift - Bitshifting in C++ producing the wrong answer -

i tried running following code code:

char c = (2 << 7) >> 7 

which should return 0 because 2 has binary representation char:

0 0 0 0 0 0 1 0 

after 7 shifts left,

0 0 0 0 0 0 0 0 

then, after 7 shifts right, get

0 0 0 0 0 0 0 0 

however, i'm getting result 2, not 0.

the compiler says 2 << 7 256, it's char , shouldn't 256.

i understand 2 << 7 calculated ints , answer put c 256 >> 7 2.

i tried cast 2 char (ex: (char)2>>7) doesn't work either.

i'm trying extract each bit char, wrote code:

char c = 0x02; for(int i=0;i<7;i++) {     char current = (c<<i)>>7; } 

how can each bit? what's wrong way?

the result of arithmetic shift operation 1 operand being int in c++ int. therefore, when write

current = (c << i) >> 7; 

c++ interpret (c << i) , (c << i) >> 7 ints, casting char when assignment done. since temporary values ints, no overflow occurs , result should come out integer result casted char.

hope helps!