python argparse, how to refer args by their name -

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this question argparse in python, easy

import argparse  parser=argparse.argumentparser()  parser.add_argument('--lib')  args = parser.parse_known_args()  if args.lib == 'lib':     print 'aa'

this work, instead of calling args.lib, want 'lib' (i dont want type more), there way export args variable out of module (ie changing scope). can directly check value of lib not specifying name of module @ front

ps: have lot of variables, not want reassign every single one

first, i'm going recommend using args specifier. makes clear lib coming from. said, if find you're referring argument lot, can assign shorter name:

lib = args.lib

there's way dump attributes global namespace @ once, won't work function's local namespace, , using globals without reason bad idea. wouldn't consider saving few instances of args. enough reason. said, here is:

globals().update(args.__dict__)

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