c# - RDLC #Error driving me nuts (per page subtotals) -

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i've got report table looking this:

usercode|recordid|originatingbranch|originatingaccount|homingbranch|homingaccount|amount|actiondate|seqno|onus|homedback

the last 2 columns booleans, contain either y or n. in fact, onus column contain ys. need have subtotal @ end of each page showing how many onus transactions there , value, , same onus transactions.

i've tried several things including described here when try i'm left nondescript #error in report. have no errors or logs or anything, #error should have number.

now i'm trying answer here, says:

  1. add additional column , enter expression: =runningvalue(fields!yourvalue.value,sum,"yourtable1"), , set hidden property true.

  2. in page header or footer, use expression: =last(reportitems!textbox12.value) subtotal of previous pages.( assume above column’s detail row textbox12)

i've put in table, expression:

=runningvalue(iif(fields!homedback.value="y", fields!amount2.value, 0),sum,"items") //my tablix called "items" , "amount" field formatted string,  //the actual value kept in "amount2"

and lo , behold, getting famous #error again. first row contains 0, , every row after contains #error.

i should note i'm not viewing report in browser or interactively or that, i'm using company's old reporting library terrible , needs rewritten (i wish), , pretty takes dataset , rdlc , spits out pdf.

is there glaringly obvious wrong expression? i'm pretty new rdlc feel i'm missing silly. there way show these #errors mean or correspond to?

another note, designed rdlc in vs2013 if makes difference.

ssrs can give #error because of data type mismatch. might evaluating amount2 string field instead of numeric. avoid such conditions explicit conversion.

try this: 

=runningvalue(iif(fields!homedback.value="y", fields!amount2.value*1.0, 0.0),sum,"items")

or

=runningvalue(iif(fields!homedback.value="y", cdbl(fields!amount2.value), 0.0),sum,"items")

or

=runningvalue(iif(fields!homedback.value="y", cdec(fields!amount2.value), 0),sum,"items")

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