mysql - Getting percentages from sql query and grouping -

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so i'm have database holds survey questions , wanting run special query don't know how it. things note: there can 2-6 answers per question depending on question.

these tables i'm using , example data:

 table: answers_only         table: questions_only ╔════════════════╦═══════════╗ ╔═════════════════╦════════════════════════════╗ ║ answer_id (pk) ║ answer    ║ ║question_id (pk) ║ question                   ║ ╠════════════════╬═══════════╣ ╠═════════════════╬════════════════════════════╣ ║    65114       ║ yes       ║ ║       123       ║ happy?             ║ ║    614         ║ no        ║ ║       1967      ║ think you're smart?    ║ ║    23          ║ ║ ╚═════════════════╩════════════════════════════╝       ╚════════════════╩═══════════╝                      table: questions ╔════════════════╦══════════════════╦════════════════╦════════════════╗ ║ unique_id (pk) ║ question_id (fk) ║ answer_id (fk) ║ person_id (fk) ║ ╠════════════════╬══════════════════╬════════════════╬════════════════╣ ║              1 ║              123 ║          65114 ║           5521 ║ ║              2 ║              123 ║          614   ║           2511 ║ ║              3 ║             1967 ║          614   ║           2511 ║ ╚════════════════╩══════════════════╩════════════════╩════════════════╝

so have table questions contains ids (fk) questions_only holds actual questions.

what i'm trying top percentage of question , order , above 90% (query). so...let's had 100 people asked 'are happy?' question. 5% said no , 95% said yes. because it's 95%, it'd show in query. on other hand, if 20% answered no on 'you think you're smart?' question , 80% said yes doesn't show up. think need next bunch of sub queries i'm not sure. here have...but know i'm way off. appreciated.

select question, answer, round(count(*)/(select count(*) questions  inner join questions_only on questions_only.question_id=questions.question_id)*100)     'percent' questions  inner join answers_only on answers_only.answer_id=questions.answer_id  inner join questions_only on questions_only.question_id=questions.question_id  group answer order count(*) desc

the end goal here find out questions easy answers, majority in favor of. 

                         wanted results query ╔═══════════════════════════════╦══════════════════╦════════════════╗ ║ question                      ║      answer      ║      percent   ║  ╠═══════════════════════════════╬══════════════════╬════════════════╬ ║  happy?               ║          yes     ║          97    ║         ║  think you're smart?      ║          yes     ║          96    ║           ║  1-5 how exciting surfing? ║            5     ║          92    ║           ╚═══════════════════════════════╩══════════════════╩════════════════╝

you should make subquery count of answers each question , join questions table:

select max(questions_only.question),        max(answers_only.answer),        (count(*)/max(t.all_count))*100 answer_percent   questions    join (             select question_id,                    count(*) all_count            questions            group question_id           ) t on questions.question_id=t.question_id    join questions_only on questions.question_id=questions_only.question_id    join answers_only on questions.answer_id=answers_only.answer_id  group questions.question_id,questions.answer_id having (count(*)/max(t.all_count))*100>=90

sqlfiddle demo


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