php - Open a hidden JavaScript form when linked from a different page -

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i don't know if there answer question, i'll try explain , hope smart enough me :).

all right:

for school have website can log in , register etc. on index there log in , register form included, hidden javascript. pressing button you'll able login or register (one of forms appear). problem: i'm checking register form php on different page, , errors outputted in form on page.

but, when go register/login page, hidden, ofcourse, , input gone user , have retype everything. <? if(isset($_post['example'])){echo htmlentities ($_post['example']);} ?> in form doesn't work anymore. putting code other page in index doesn't seem option.

thanks in advance response,

paul

edit - i'll post code make clearer. javascript hide , toggle:

'$(document).ready(function(){ $("#login").hide(); $("#registerincl").hide(); $("#loginb").click(function(){ $("#login").toggle(); $("#loginb").hide(); $("#guest").hide(); $("#registerincl").hide(); $("#register").hide(); $("#hh").hide(); }); $("#register").click(function(){ $("#registerincl").toggle(); $("#register").hide(); $("#loginb").hide(); $("#guest").hide(); $("#hh").hide(); $("hr").hide(); }); $('#guest').click(function() { window.location='guest.php'; }); });'

ofcourse link register validation page:

<form action="/register" method="post" target="">

and of php code

if (isset($_get['success']) === true && empty($_get['success']) === true) { echo 'je bent geregistreerd. ga naar je email en activeer je account!'; } else { if (empty($_post) === false && empty($errors) === true) {     $register_data = array(         'username'      => $_post['username'],         'joined'        => $_post[$time],         'password'      => $_post['password'],         'first_name'    => $_post['first_name'],         'last_name'     => $_post['last_name'],         'email'         => $_post['email'],         'email_code'    => md5($_post['username'] + microtime())     );            register_user($register_data);     header('location: register.php?success');     exit();  } else if (empty($errors) === false) {     //echo output_errors($errors);             }    <form action="/register.php" method="post">         <ul class="login">             <li>                 <h1>we konden je niet registreren!</h1>                 <?php                     echo output_errors($errors);                 }                 ?>             </li>             <li>                 <br><br><br><a href="index">probeer opnieuw</a>             </li>         </ul>     </form>

you want build form without action, leaving fields are.

with jquery should add event handler form submit prevents default action proceeds grab form data , ajax php class deals registration. can handle success , error events , need returned data. link below explains how reply javascript php json data.

here sample ajax request event handler can see i'm talking above. can find nice , comprehensive tutorial here 

$(function() {   $(".button").click(function() {     // validate , process form here   }); });  $.ajax({   type: "post",   url: "bin/process.php",   data: datastring,   success: function() {     $('#contact_form').html("<div id='message'></div>");     $('#message').html("<h2>contact form submitted!</h2>")     .append("<p>we in touch soon.</p>")     .hide()     .fadein(1500, function() {       $('#message').append("<img id='checkmark' src='images/check.png' />");     });   } });

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