c++ - Deducing template parameter from default parameter -

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this question has answer here:

why doesn't c++11 program work:

template <typename t> void f(t t = 42) {}  int main() { f(); }

why can't t deduced default argument 42?

14.8.2.5 [temp.deduct.type]:

19 - template type-parameter cannot deduced type of function default argument. [...]

the example given substantially same yours.


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