java - Extending a class in the method signature -
can explain does? generics question since i'm learning in java tagged java. public static <t extends comparable<? super t>> void quicksort(t[] list) {...} what don't understand part: <t extends comparable<? super t>> i have tried looking @ this doesn't seem explain in clear way. my guess is: genetic type t extends comparable interface requires generic type superclass of generic type. don't understand this. example: public class x implements comparable<x> { } the class x implements comparable satisfies extends comparable , generic parameter of comparable x because x super x ( java generics super keyword ) another example: public class y {} public class x extends y implements comparable<y> { } another example: public class x implements comparable<object> { } but won't work: public class {} public class x implements comparable<a> { } as class x comparable objects not in i...
